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What is the solution to the equation 49x=sqrt 7^(2x+6)
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\[\Large 49x = \sqrt{ 7^{(2x+6)}}\]Like that?
yes
Take square on both sides, you will get \[\large (48x)^2 = 7^{2x+6}\]
That's 49 not 48
ohhh now i remember that lesson. Thanks :)
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\[\Large (49x)^2 = 7^{2(x+3)}\] \[\Large (7^2x)^2 = 7^{2(x+3)}\]
\[\Large 49x = 7^{(x+3)}\]
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