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5^7x-2=4^x solve the equation
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\[\LARGE 5^{7x-2}=4^x\] ?
5^(7x-2)=4^(x) ln5^(7x-2)=ln 4^(x) 7xln5 -2ln 5- xln4 = 0 x= 2ln 5 / 7ln 5- ln4 x = aprox. 3.2189
i have another on its 2^4x+2=8^x
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