Question

find all imaginary and real zeros

g(x)=x^3+9x^2+25x+25
explain please

Answer 1

Did you check for any rational zeros yet?

Answer 2

What are factors of 25:
\[\pm1,\pm5,\pm25\]

See if any of these numbers I listed are zeros

:)

Answer 3

-5

Answer 4

only zero is -5

Answer 5

\[g(-5)=(-5)^3+9(-5)^2+25(-5)+25=0\]
So that means x=-5 is a zero
So x+5 is a factor (since x=-5 means we had x+5=0 )

But anyways if x=-5 is a solution then
you can find the other zeros by synthetic division + quadratic formula