Solve the exponential equation using logarithms, rounding the answer to the nearest thousandth (3 decimal places). Show your work.
2 = 7^x+3

Question

Solve the exponential equation using logarithms, rounding the answer to the nearest thousandth (3 decimal places). Show your work.    
2 = 7^x+3

anonymous · Answer

i'm assuming you mean 2 = 7^(x+3) ?? or is it 2 = 7^x + 3

anonymous · Answer

no its 2=7^x+3

anonymous · Answer

no solution then... boy that was easy huh?

anonymous · Answer

ok..
since its the second one i wrote down, if you subtract 3 from both sides, you'll get:

-1 = 7^x

correct?

anonymous · Answer

correct

anonymous · Answer

now, 7^x will never ever forever be negative, no matter what x value you put in...

anonymous · Answer

in other words, 7^x will always be a positive number.  so there is no solution to your original equation.

anonymous · Answer

ok sounds good

anonymous · Answer

ok... have a good one man.. :)