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A golf ball is hit from the ground with an initial speed of 192 feet per second. Assume the starting height of the ball is 0 feet. How long will it take the golf ball to hit the ground?
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12 secs 19 secs 39 secs 6 secs
What equation models this? It is impossible otherwise, unless we are suppose to draw from other models.
Remember that the equation of the motion \[ s(t) = -\frac 12 g t^2 + v0 t + s0 \] Where g=9.8; v0=192 and s0 =0 It is clear that t=0 the ball is on the ground. What other values make s(t)=0. In other words, solve s(t)=0 for t. And you are done.
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