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I have a working answer of 6 for XT but I have to check and post my work.
If a tangent segment and a secant segment are drawn to a circle from an outside point, then the square of the tangent length is equal to the length of the entire secant segment times the length of its external segment. (TZ) ^2 = (SZ) * (YZ) 6^2 = SZ * 4 SZ = 9 ---------- SZ = SX + XY + YZ 9 = 3 + XY + 4 2 = XY and then ...
mine was the wrong one...
If two chords intersect within a circle, the product of the lengths of the segments of one chord is equal to the product of those of the other chord. SX * XY = WX * XT 3 *2 = 1 * XT XT = 6
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Check my work, please.
Absolutely correct. Thanks ^^
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