Question

how do you solve. (2y^2)^-2/x

Answer 1

\[\Large \frac{(2y^2)^{-2}}{x}?\]

Answer 2

yes

Answer 3

since it's negative exponent..bring it to denominator

\[\Large \frac{1}{x(2y^2)^2}\]

just expand

Answer 4

I'm thinking its