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Help with proof.
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see first EG is passing through center & perpendicular to AB .k!
yeah, but what can you do with the right angles? I just know that you must prove that that AD=BC
k! i have a prove u see it.
nope
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k! now we must learn a theorem that a line segment from center perpendicular to a chord inside a circle bisects the chord,i.e.; AG=GB.
now we will prove that \[\Delta AGE \] IS congruent to \[\Delta BGE\]
1.AG=GB 2.ang. AGE=ang.BGE=90 3.GE=GE=common segment Thus , from SAS congruency \[\Delta s\] are congruent
I got it. Thanks.
happy to help:)
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