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find derivative of csc(5x).
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There are a couple of ways to do this. Some people like to memorize the derivative formulas for each trigonometric function. I tend to just derive them each time. So, csc(5x) is the same as 1/sin(5x). We use the quotient rule followed by the chain rule, so -5cos(5x)/sin^2(5x), or -5cot(5x)csc(5x)
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