Question

∫x sin^-1(x^2) dx

Answer 1

do you know how to use integration by parts?

Answer 2

yes

Answer 3

let u = \(\sin^{-1} (x^2)\) dv = \(xdx\) have you tried that?

Answer 4

but wouldn't that you have to integrate become more complicated?

Answer 5

why do you think so?

Answer 6

youll just integrate xdx

Answer 7

do the u-sub u=x^2 first

Answer 8

then you can do parts...

Answer 9

uhmm yeah what he said

Answer 10

o.O i understand now thanks!