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Factor completely: 2cb + 7cx + 2b + 7x
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factor by grouping
we can group the terms like this: (2cb+7cx)+(2b+7x) then factor out a c from the first term and a 1 from the second term and we get: c(2b+7x)+1(2b+7x) The simply we get: (c+1)(2b+7x)
aww thanks
Factor completely: 21x3 + 35x2 + 9x + 15
thx @LagrangeSon678
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@phi is this correct
@kirbykirby @zzr0ck3r
@Nurali
is this correct
Yes @Law&Order
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thx ;)
My Pleasure.
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