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Mathematics 19 Online
OpenStudy (anonymous):

Factor completely: 2cb + 7cx + 2b + 7x

OpenStudy (anonymous):

factor by grouping

OpenStudy (anonymous):

we can group the terms like this: (2cb+7cx)+(2b+7x) then factor out a c from the first term and a 1 from the second term and we get: c(2b+7x)+1(2b+7x) The simply we get: (c+1)(2b+7x)

OpenStudy (anonymous):

aww thanks

OpenStudy (anonymous):

Factor completely: 21x3 + 35x2 + 9x + 15

OpenStudy (anonymous):

thx @LagrangeSon678

OpenStudy (anonymous):

@phi is this correct

OpenStudy (anonymous):

@kirbykirby @zzr0ck3r

OpenStudy (anonymous):

@Nurali

OpenStudy (anonymous):

is this correct

OpenStudy (nurali):

Yes @Law&Order

OpenStudy (anonymous):

thx ;)

OpenStudy (nurali):

My Pleasure.

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