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Please help with log2(1/8)=3 and what does this function look like f(x)=-2log3x
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Well the first equation is not true. Where did you get it?
The 2 is below log and its -3 not 3 sorry
Yes. Now it is true. So what do you want help with?
I need to change the log expression to an equivalent expression involving an exponent.
What is the base?
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2
What is the exponent?
-3
So write that much. The base is 2, the exponent is -3
What do I do with the 1/8
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