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Which statement must be true to prove that segment DE is parallel to segment CA? 3 : DC = 5 : EA 3 : EA = 5 : DC 1 : DC = 4 : EA 1 : EA = 4 : DC
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"Poop.jpg"
lol i couldnt think of anythig else to name it at the moment
Okay, well first of all, to have those two sides parallel, I'd like for the angles E and A to be congruent. Also angles C and D. That would make those two triangles similar. So, similar triangles is what you're aiming for. Similar triangles have proportional sides.
ok
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so it would be the first one
Right.
why thank you very much :D
You're quite welcome, good sir.
im a girl :(
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Haha sorry, m'lady. I don't know why I never noticed that response. =/
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