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find the value of "a" if the points are the indicated distances apart.
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\[(2,a) \] and \[(-3,-2) \] when \[d=\sqrt{34}\]
d=sqrt34 =\[\sqrt{(-3-2)^2+(-2-a)^2}\] now square both sides and you get 34=\[25+(-2-a)^2\]
\[d=\sqrt {25+4a^2}\]
like that is how it should look right?
(-2-a)^2=4+2a+2a+a^2=4+4a+a^2 so 25+a^2+4a+4=34 so a^2 +4a+4=9 a^2+4a-5=0 whcih factors to (a-1)(a+5) can you go from here?
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b, (-2-a)^2 does not equal 4a^2
im completly lost now
hang on
how did you get -5
it's 1 but I want him to have an explanation
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hold on Radar is going to help
4+(-9)=-5
oh okay you moved the 9 over
right
the answer is 1 but I want radar to give an explanation/confirmation because he has been observing
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