How would you sketch this curve y=(e^x)/(x)
finding zeros, max/mins, inflection points and asymptotes?

Question

How would you sketch this curve y=(e^x)/(x) 
finding zeros, max/mins, inflection points and asymptotes?

anonymous · Answer

i was wondering how you would draw the other side of the graph, as i cant find any of the points thru 1st/2nd derivative

anonymous · Answer

y'=e^x[(1/x)-(1/x^2)]=0  x=1 , y=e  , y''=e^x[(1/x)-2(1/x^2)+2(1/x^3)] >0 for x=1
so (1,e) is min point(local) if x=0 then y=inf so x=0 (vertical) is asymptomatic line , if x=+inf then y=+inf ,
if x=-inf then y=0 so y=0 is asymptomatic line ( horizontal) 
try to plot it is simple!

anonymous · Answer

ive tried to plot it and i get a min at (1,e) but i dont know how the other part of the graph would look

anonymous · Answer

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