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factor 1 -- 16y ^2 - 2y + 16
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its really simple use quadratic formula
well i know how to do it but not with the division symbol
1/(16y^2-2y+16) is it like this???
Factor a 2 out of the denominator
is it 4
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the 16 is 4 * 4 = 16
\[\frac{1}{16y^2-2y+16}=\frac{1}{2(8y^2-y+8)}\]
thats the answer ?
Well, it won't factor any further unless you are supposed to find the non-real factors of the denominator. Exactly what do the directions say?
factor that's all
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Then that's it.
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