Question

how to solve this equation: √3-x=x-1

Answer 1

is this your question?
\[\sqrt{3-x}=x-1\]

Answer 2

yes

Answer 3

\[\sqrt{3-x}=x-1\]
1. square both sides
\[\sqrt{3-x}^2=(x-1)^2\]\[3-x=x^2-2x+1\]\[x^2-x-2=0\]
Can you solve it now?

Answer 4

that's as far as i got i didnt know what to do there?

Answer 5

Solving quadratic equation... either factorise it or applying the quadratic formula..

Answer 6

oh okay i got x=2 and x=-1

Answer 7

Yes !~

Answer 8

it should be ''or'' not ''and''

Answer 9

it's x=2

Answer 10

Oh... I forgot a step. You need to put the answer back into the equation and check it. If the right hand side has a negative value, you need to reject it!

Answer 11

So, x=-1 would not be the answer :|