Question

Solve: [0,π]
sinx-sinxcosx=0

Answer 1

x=0 is a solution

Answer 2

your a genius... -.- smh

Answer 3

cosx=1
x=arcos1

Answer 4

ohh arc... alright.. how do you do the arc problems again, been ages (review for finals is a feather.. lol)

Answer 5

\[\sin x-\sin x \cos x=0\]\[\sin x(1-\cos x)=0\]
\[\sin x=0\] when \[x\in n\pi\]\[n \in R\],
there are only two point in the domain