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x^3+1/8 factor
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Think about \[a^3 + b^3=(a+b)( a^2 - a b + b^2) \]
You a= x and b =1/2
yea i did still dont understand
\[\frac{1}{8}= \frac{1}{2*2*2}=\frac{1}{2^3}=2^{-3}\]
\[ x^3 + \frac 1 8= x^3+\left(\frac 1 2\right)^3= ( x+ \frac 1 2)( x^2 - \frac 1 2 x+ \frac 1 4) \]
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