Going against the current, a boat takes 6 hours to make a 120-mile trip. When the boat travels with the current on the return trip, it takes 5 hours.
If x = the rate of the boat in still water and y = the rate of the current, which of the following systems could be used to solve the problem?
6(x - y) = 120 and 5(x + y) = 120
6(x + y) = 120 and 5(x - y) = 120
6x - 5y = 120 and x + y = 120

Question

Going against the current, a boat takes 6 hours to make a 120-mile trip. When the boat travels with the current on the return trip, it takes 5 hours.
If x = the rate of the boat in still water and y = the rate of the current, which of the following systems could be used to solve the problem?
6(x - y) = 120 and 5(x + y) = 120
6(x + y) = 120 and 5(x - y) = 120
6x - 5y = 120 and x + y = 120

anonymous · Answer

going against the current speed becomes x-y and for the return it becomes x+y so 
6(x-y)=120 and 5(x+y)=120 is the answer