Question

If an object falls five meters during the first interval of time, what is the total distance fallen at the end of the second interval of time?

Answer 1

\[S=ut +(1/2) g t ^{2}\]
here u= 0 (since the object falls, it is not thrown)
puttiing S= 5 m
And g= 10 m/s^2
you get t=1 sec
now, after second interval of time time (t) = 2 sec
substitute it in above equation, you get S=20 m