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Given: rectangle ABCD is similar to rectangle ZBXY. Enter answer as a simplified, improper fraction.
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what are we supposed to solve>?
If BX = 8, BZ = 3, DC = 5, then XC =
do you have a picture of the rectangle?
i do but it wont go on here..\
why not?
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|dw:1336662646508:dw|
hold on ok let me see if i cn find one
well due to similar rectangles,, BZ/CD = BX/BC..substitute values and get BC..from there,,XC=BC-BX..hope this helps..
|dw:1336662854160:dw| does it look sumthng like this
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