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Mathematics 13 Online
OpenStudy (anonymous):

(t+2)^2=4

OpenStudy (saifoo.khan):

take a square root on both sides. \[\sqrt{(t+2)^2} = \sqrt4\]

OpenStudy (saifoo.khan):

\[t + 2 = \pm 2\]

Parth (parthkohli):

\(\Large \color{purple}{\rightarrow t + 2 = \pm2 }\) \(\Large \color{purple}{\rightarrow t = 0 }\) or \(\Large \color{purple}{t = -4 }\)

OpenStudy (saifoo.khan):

therefore, t +2 = 2 t + 2 = -2

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