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Mathematics 9 Online
OpenStudy (anonymous):

sinx=5/13 find sin2x

Parth (parthkohli):

\(\Large \color{purple}{\rightarrow sin^2x = ({5 \over 13})^2 }\) \(\Large \color{purple}{\rightarrow sin^2x = {25 \over 169} }\) You meant \(sin^2x\) right?

OpenStudy (anonymous):

no i did not but thanks anyway I just figured it out.

OpenStudy (anonymous):

Out of curiosity, what is your answer SandyHearts? :)

OpenStudy (anonymous):

120/169

OpenStudy (anonymous):

double angle formula is sin2X = 2sinXcosX

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