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Mathematics 13 Online
OpenStudy (anonymous):

The figure shows a weather balloon at point P. How high is the point P of the weather balloon from a point R on the ground?

OpenStudy (anonymous):

How high is the point P of the weather balloon from a point R on the ground?

OpenStudy (anonymous):

@lalaly cud u help

OpenStudy (lalaly):

since u are given an angle and a side of a right triangle use \[\tan(\theta)=\frac{opposite side}{adjacent}\]\[\tan(32)=\frac{RP}{5}\]

OpenStudy (lalaly):

now solve for RP

OpenStudy (anonymous):

5 by sec 32 degrees miles 5 by cot 32 degrees miles 5 cosec 32˚ miles 5 cot 32˚ miles

OpenStudy (anonymous):

@lalaly

OpenStudy (lalaly):

Oh never mind i got it lol its the second choice 5 by cot32

OpenStudy (anonymous):

lol! thank u

OpenStudy (anonymous):

@lalaly

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