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OpenStudy (anonymous):

a person can see the top of a building at an angle of 65 degrees. the person is standing 50 ft away from the building and has an eye level of 5 ft. how tall is the building to the nearest of a foot?

OpenStudy (anonymous):

\[50*\text{Tan}[65{}^{\circ}]+5=112 \text{ feet} \]

OpenStudy (anonymous):

ok wait can u explain that to me im soo lost Lol

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