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Find the probability. An IRS auditor randomly selects 3 tax returns (without replacement) from 47 returns of which 5 contain errors. What is the probability that she selects none of those containing errors? A. 0.0012 B. 0.0006 C. 0.708 D. 0.7136
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of the 47, 5 contain errors and so 42 do not. probability of selecting 3 that do not is \[\frac{42}{47}\times \frac{41}{46}\times \frac{40}{45}\] hope it is clear where the numbers come from
first one doesn't AND second one doesn't given first one doesn't AND third one doesn't given the first two don't
so what would my anwser be?
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