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Mathematics 7 Online
OpenStudy (anonymous):

How would I manage to get this to a form that I can use to graph a hyperbola? 36x^2-y^2-24x+6y-41=0

OpenStudy (anonymous):

put it in standard for so you can identify the center, transverse, conjugate axes, etc....

OpenStudy (anonymous):

(x-h)^2/a^2 - (y-k)^2/b^2 = 1

OpenStudy (anonymous):

you will probably need to complete the square to get it in that form.

OpenStudy (anonymous):

I think I got it.. let me work at it a bit

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

thanks, I got it. I was just factoring wrong, hahah.

OpenStudy (anonymous):

ok...

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