The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X.

What is the measure of angle ACB?

6, 12, 24 or 32 degrees

Question

The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X. 

What is the measure of angle ACB?

6, 12, 24 or 32 degrees

anonymous · Answer

attachment

anonymous · Answer

@pfenn1  can you help me please?

anonymous · Answer

the answer is 12 :)

pfenn1 · Answer

@Kris5, could you show how you got the answer, not just the answer?

anonymous · Answer

Sure, <XBA is an inscribed angle. Therefore, it is twice the measure of its intercepted arc. Its intercepted arc is arc XA. So... arc XA= 2m<XBA... arc XA=2(64)...arc XA=128.
Now< ACB= 1/2 (BA-XA)... <ACB=1/2(152-128)...<ACB=1/2(24)...<ACB=12 :)