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OpenStudy (anonymous):
write as a system of 1ST order differential equation 5y''-10y'+25y=0
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OpenStudy (anonymous):
Let x1=y x2=y' => x1' = y' = x2 => x2' = y'' = 2y' - 5y(from the equation given) hence we have x2' = 2x2 -5x1
OpenStudy (anonymous):
thanks
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