An obj. that is projected straight up with an initial velocity v feet per second and initial height s feet, t is time in seconds. trent throws a baseball straight upward with a velocity of 44 feet per second from a height of 12 feet.In how many seconds will the ball hit the ground?

Question

anonymous · Answer

initial velocity u = 44ft/sec
s= ut + 1/2 a t^2
-12 = 44t + (0.5)( -32.2) t^2  (assume a=32.2ft/sec)
16.1t^2 -44t -12 = 0
so t = { -(-44) + sqrt[(-44)^2 -4(16.1)(-12)]} / (2*16.)
t=2.98 sec