Question

Solve the equation z^2 -2iz -5=0
giving answers in the form x+iy
where x and y are real

Answer 1

treat z as ordinary variable and i as ordinary constant,,this is a simple quadratic eqn then.. then it should be easy to solve..

Answer 2

I got to \[2i {+ -}\sqrt{4i^2 +20} \over 2\] What now?

Answer 3

well,,whata i^2 mam ?

Answer 4

whats*

Answer 5

-1?

Answer 6

yes..thats right..
so you have the solution now i guess..

Answer 7

Yes. Thanks :)

Answer 8

its i+2 and i-2 ..