Question

How do I prove this identity: (sinx-cosx)^2 = 1-2sinxcos?

Answer 1

let a = sinx
b = cos x

(a+b)^2 <----do the square of a binomial

Answer 2

so it's (a+b)^2? not (a-b)^2?

Answer 3

(a-b)^2 <---do the square of a binomial

sorry typo

Answer 4

(sinx-cosx)2
Sin^2x-2cosxsinx +cos^2x
1-2cosxsinx

Answer 5

bcoz (sinx)^2 + (cosx)^2 =1

Answer 6

ohhhh!

Answer 7

did you already know how to solve it @milliex51