the largest number that leaves reminder 7 and 8 when divided by 3248 and 4175 respectively is??
the answer is 463
plzzz do it
i posted this question once and no one gave the steps so i reposted it
plzz i think chand got it
Please don't start a new thread about this question. This is already been discussed ad nauseam in that earlier thread and we have explained it you why this question is not correct.
hey question is not wrong............
u say it is wrong becozz u cant solve it
according to the problem, 3248 = xy +7 and 4175 = xz +8 where "x" is the divisor and y,z are the respective quotients. divide both the equations. you get y/z = 7/9
are you clear until now?
yes
@chand: He thinks that you got it, you might like to explain your standpoint.
yes i knw i suggested this method earlier u se..
chand plzz go on
so, let y = 7 and z = 8. this satisfies the equation and gives us x= 463
Pheww :/ I am out of this thread.
how on dividing we get y/z=7/9
xy = 3241 and xz = 4167. divide these
ok then how y = 7 and z = 8
basically the question you typed is wrong. you said, " when the number is divided by 3248 and 4175" it should've been " when 3248 and 4175 are divided by " let y = 7k and z=8k. the only value of k satisfying the equation is k=1. so we take y=7 and z=8
ok thzzz plzzz help http://openstudy.com/study#/updates/4fad2c5be4b059b524f8b3f7
oh sorry i typed it wrong
@FoolForMath hope the question now makes some sense.
It's still the not the largest number.
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