f(x)=x^2-2x-3
\(\Large \color{purple}{\rightarrow f(x) = x^2 - 3x + x - 3 }\) \(\Large \color{purple}{\rightarrow f(x) = x(x - 3) + 1(x - 3) }\) \(\Large \color{purple}{\rightarrow f(x) = (x + 1)(x - 3) }\)
answers are: A. (-1,-4). B. (-1,-2). C.(1,-4). D.(1,-2).
so what's the question then?
@ParthKohli factored the expression for you... it should be easy finding the zeros.
f(x)=\[x^2-2x-3\]
1 and -3?
thats not one of my answers!
What is your question ? to factor ?
all you have is an equation up there, what's the question?
she's gone!
-1 and 3 should be the answers.
Oh thats right !!
But thats not one of the choices
still, that's not one of the choices... :)
i know
the question is determine the vertex of the parabola formed by f(x)=x^2-2x-3.
Check for some mistake in the question or the choices again please.
there is no mistake.
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