Question

A block B of mass 5 kg is attached to one end of a light inextensible string. A particle P of mass
4 kg is attached to other end of the string. The string passes over a smooth pulley. The system is in
equilibrium with the string taut and its straight parts vertical. B is at rest on the ground.
State the tension in the string and find the force exerted on B by the ground.

Answer 1

Consider block B at equilibrium,
R+T= 5g
Consider particle a at equilibrium,
T= 4g (This is the tension)

R + 4g = 5g
R = g (normal reaction , i.e force exerted on B by groud where "g" is acceleration due to gravity)

Answer 2

thank you

Answer 3

youre welcome!