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I CANT GET ANY HELP!!!! PLEASE HELP!!! BC is tangent to circle A at B and to circle D at C. AB = 10, BC = 25, and DC = 3. Find AD to the nearest tenth. Hint: Draw an auxiliary line from D to BA. Choices: A. 26 B. 28.2 C. 25.2 D. 26. 9
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What's all the shouting abut?
After constructing the auxiliary line as suggested u have a triangle with legs of 7 and 25 and you want the third leg which is simple Pythagorus.
A. 26 -----------
Theorems Used: Through a point outside a line, exactly one line perpendicular to the given line can be drawn. A tangent to a circle is perpendicular to a radius drawn to the point of tangency. The sum of the interior angles of a quadrilateral is 360. Pythagorean Theorem
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