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Solve: Sq Root 3x=4-3=7
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\[\sqrt{3x+4}-3=7\]
\[\sqrt{3x+4}=11------------>3x+4=121\] rest it's easy
why 11?
sry 10. :)
and the check should equal 7?
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3x=96 x=32
thats what I got but the check wont go back to 7
is it sqrt(3x+4)-3 or sqrt(3x+4-3) ?
just the first one
\[\sqrt{3x+4}-3=7\]
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3x+4=100 3x=96 x=32 don't know what esle to say....
ty
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