Circle A has an equation of x2 + (y + 3)2 = 16. Where is the center of the circle located?
on the x-axis

in the third quadrant

on the y-axis

in the first quadrant

Question

Circle A has an equation of x2 + (y + 3)2 = 16. Where is the center of the circle located? 
on the x-axis

in the third quadrant

on the y-axis

in the first quadrant

anonymous · Answer

well i worked on it & got an answer but i'm not sure if it is right
would u like to k it ?

anonymous · Answer

sure

anonymous · Answer

ok
x^2+ (y+3)^2=16
X^2+Y^2+6y+9=16
therefore: -X^2=Y^2+6Y-7
so we need another equ. to solve the 2 variables that what i couldn't reach sorry

anonymous · Answer

its ok

anonymous · Answer

but thank u

anonymous · Answer

its on the y axis, since the center is equal to (0,-3)