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Mathematics 19 Online
OpenStudy (anonymous):

Help!!!!!!!!! Exponential Functions

OpenStudy (anonymous):

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OpenStudy (mertsj):

Remember that the bottom number is the root. So you need to figure out a number such that (number) to the fifth power = 243.

OpenStudy (mertsj):

What is that number?

OpenStudy (campbell_st):

look at \[243 = 3^5\] so the problem is \[-(243)^{\frac{1}{5}} = -(3^5)^{\frac{1}{5}}\] using the power of a power index law \[-(3^5)^{\frac{1}{5}} = -(3) \] or -3

OpenStudy (anonymous):

Thanks

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