Question

Hi, can anyone tell me how to solve: 1/|12x-3| less than and equal to 9, and express it in proper interval notation? Thank-you!

Answer 1

abs(12x-3)>=9 then 12x-3>=9 or<=-9
x>=1 or x<=-1/2

Answer 2

Hi, thank-you for your help, but I don't think that's the right answer. Shouldn't the (12x-3) be multiplied over to the 9 side since orig it was in the denominator? Something like:
1=<9|12x-3|, im not sure where to go from there...