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Evaluate. 8!/5!3! 0 1 56
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56
this is \[\frac{8\times7\times6\times5!}{5!\times3!}\] delete the common factor of 5! and 3! = 3 x 2 x 1 = 6 so the problem is now \[\frac{8\times7\times6}{6} = 56\]
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