Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

Factor by grouping: show work please!!! 6r^3+15r^2+8r+20

jimthompson5910 (jim_thompson5910):

6r^3+15r^2+8r+20 (6r^3+15r^2)+(8r+20) 3r^2(2r+5)+(8r+20) 3r^2(2r+5)+4(2r+5) (3r^2+4)(2r+5) So 6r^3+15r^2+8r+20 completely factors to (3r^2+4)(2r+5)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!