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help me in this..its graphing quadratic functions
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\[x ^{2}-5x+12\]
y=x^2-5x+12 you can try to find 'special' points 1) let's find x intercept 2) let's find y intercept 3) let's find vertex
I am sure you know 1) and 2) so let's do 3)
i know tht the axis of symmetry is 5/2
thats how i start..
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good, plug that into function to find veterx
k
23/4 is vertex or 5 3/4
good, now since it is positive x^2 , it will face up
yep
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