Question

need help solving please..
solve using quadratic formula
-2t^2+4t+3=0

Answer 1

\[-2t ^{2}+4t+3=0\]\[-(4)\pm \sqrt{(4)^{2}-4(-2)(3)}/2(-2)\]\[-4\pm \sqrt{40}/-4\]

Answer 2

\[-4\pm 2\sqrt{10}/-4\]

Answer 3

answer given is \[2\pm \sqrt{10}/2\]

Answer 4

hmm......
you will get two value for t
Hope this helps you :)