Question

solve quadratic equations-
Solve:
2x^2+1=0

Answer 1

complete the square or use the quadratic equation.

Answer 2

quadratic formula

Answer 3

http://upload.wikimedia.org/wikipedia/en/math/8/e/4/8e4fef5352eb498b3534af481c8c4fd4.png

Answer 4

this is what i've done so far \[2x ^{2}+1=0\]\[2x ^{2}=-1\]\[x ^{2}=-1/2\]\[x=\sqrt{-1/2}\]
answer is \[\pm \sqrt{2}/2i\]

Answer 5

crap i think it will be a complex number :(

http://www.numberempire.com/cgi-bin/render2.cgi?%5Cnocache%20%5CLARGE%20x%3D%7B%7Bi%7D%5Cover%7B%5Csqrt%7B2%7D%7D%7D%20%20%24%24

Answer 6

\[x^{2} = -1/2\]
\[x = \pm (\sqrt{2}/2) i \]

Answer 7

thats the right answer glgan1, what step am i missing?