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Find all values of x such that sin (2x) = sin x and \(0 \le x \le 2\pi\). How do I do this?
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write sin2x as 2sinxcosx, then divide both sides by sinx, then divide by two, leaving cosx = 1/2. can you do it from there?
do i get the \(\cos^{-1}\) of 1/2?
yes, which has two values on the unit circle
my calculator says 60...
pi/3 or 5pi/3
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expand sin(2x) and cancel out sin(x)
i get pi/3 equals 60...but where did 5pi/3 come from o.O
|dw:1336794614729:dw| this MUST be in radians igbiw..
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