complex numbers chapter :
how to find arguments of roots
(1/2)+i(square root 3/2) or
(1/2) -i(square root 3/2)

please help. what is argument in the first place of complex numbers chapter!!

Question

complex numbers chapter :
how to find arguments of roots
(1/2)+i(square root 3/2) or
(1/2) -i(square root 3/2) 

please help. what is argument in the first place of complex numbers chapter!!

anonymous · Answer

for christ's sake, someone help !

anonymous · Answer

(1/2)+i(square root 3/2)
->a = 1/2,   b = sqrt 3/2
=> tan (theta) = sqrt3 
Thus argument is 60 degree  ( pi/3)

anonymous · Answer

@jesonpeson WHERE are you?

anonymous · Answer

the tan(theta) = sqrt 3 , i didnt understand this part but ur answer is right ! please explain this part ~!!

anonymous · Answer

Of course, it should be correct :P
tan (theta) = b/a

anonymous · Answer

OHH~!! hahaha thanks alot chlorophyll !! finally. :D cos apparently i'm having my alevel cambridge exams coming this may 16 on P3. 
thank you.

anonymous · Answer

My pleasure :)

anonymous · Answer

muacks~ :p

anonymous · Answer

It took me a while to figure out the term " root argument" is ANGLE :P