Question

a body dropped from a tower travels half of the distance in the last second of its motion the total time of fall will be?(g=10m/s^2)

Answer 1

do you know the formula for the distance travelled in nth second of motion?

Answer 2

yes d=u+a(n-1/2)

Answer 3

d/2=10(n-1/2)
d=10(2n-1)
d=1/2*10*n^2
=5n^2
5n^2=20n-10
5n^2-20n+10=0
n^2-4n+2=0
n^2-4n+4=2
(n-2)^2=2
n-2=sqrt2
n=sqrt2+2

Answer 4

s u r correct