Question

The faces of a tetrahedron die are numbered 1 to 4. Each of the 4 sides is equally likely to land down.
What is the probability that the 2 does not end up face down?
1/4
3/4
1

Answer 1

This can happen only in one outcome, and the total number of outcomes is 4.

P(Event) = Preferred number of outcomes over total number of outcomes.

Answer is \(\Large {1 \over 4}\)